# Radius of earth at pole and equator

The **radius of Earth** at the **equator** is 3,963 miles (6,378 kilometers), according to NASA's Goddard Space Flight Center. However, **Earth** is not quite a sphere. The planet's rotation causes it to bulge at the **equator**. **Earth's** polar **radius** is 3,950 miles (6,356 km) — a difference of 13 miles (22 km).

**At** the **equator**, the rotation of the **earth** causes it to bulge. The polar **radius** **of** **Earth** is 3,950 miles (6,356 km), a 13-mile difference (22 km). The diameter of the **Earth** **at** the **equator** is 12,756 kilometers (km). How Do We Calculate Distances of This Magnitude? ... but not quite, a perfect sphere. The **Equator** is the parallel line located at 0°00’00”. It is identified as the latitude that falls at the point that is equidistant from the North **Pole** and the South **Pole**. The **Equator**’s covers a distance on the **Earth**’s surface approximately 24,901 miles long. The sun is perpendicular to the **Equator** twice a year in March and September.

Except at the **poles** **and** the **equator**, phi differs from the geocentric latitude phi'. The point on the **Earth** surface directly below a given point above the surface is not on a N: the **radius** **of** curvature in the prime vertical: N = a [1 - f (2 - f) sin2(phi)]-1/2. The inverse conversion can be iteratively computed from.

The equatorial **radius of earth** formula is defined as is the distance from the center **of Earth** to a point on its surface. Its value ranges from a near-maximum 6,378 km at the **equator** to a near minimum 6,357 km at either **pole** is calculated using **Radius of Earth** = Geostationary **radius**-Geostationary height..It is obvious that the points on the **Equator** revolve on a circle with the. a_diff = GM*(1/(r_**equator**) 2 - 1/(r_**pole**) 2), where:. G = 6.674×10-11 N⋅m 2 /kg 2 [the gravitational constant], M = 5.972 × 10 24 kg [the mass of the **Earth**], r_**equator** = 6,378,137 m [the equatorial **radius**], r_**pole** = 6,356,752 m [the polar **radius**]. Calculating it through, a_diff = 9.798 m/s 2 - 9.864 m/s 2 a_diff = -0.066 m/s 2. Therefore, a person or (or object with mass negligible.

May 11, 2022 · If the **earth** had a **radius** of 10cm at the **poles** it would have a **radius** of 10,03cm at the **equator**. That’s a 0.3mm increase, you would not notice that difference unless you measured it with precision tools. Let’s look at another analogy. If you have one dude that’s 175cm tall and another that’s 0.3% taller he would only be. A point at **pole** is closer to the center of **Earth**. Consequently, gravitational acceleration is greater there than at the **equator**. For example, shape of **Earth** accounts for actual change in the gravitational acceleration as polar **radius** is actually smaller than equatorial **radius**. **Eratosthenes** made a remarkably precise measurement of the size of the **earth**. He knew that at the summer solstice the sun shone directly into a well at Syene at noon. He found that at the same time, in Alexandria, Egypt, approximately 787 km due north of Syene (now Aswan), the angle of inclination of the sun’s rays was about 7.2°.

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Of course if the **earth** were a fluid of uniform density, it would take on a shape such that the effective would be normal to the surface of the fluid. Newton calculated that this would make **radius** of the **earth** at the **equator** one part in 230 larger than the **radius** at the **poles**. The **earth** would take on the shape of an oblate spheroid. With much of. Geocentric gravitational constant Equatorial **radius** **of** the **Earth** Dynamical form factor Nominal mean **Earth's** **of** the **pole** **at** J2000.0 relative to the ICRS celestial **pole** has been estimated by using (a) the The ICRF positions are independent of the **equator**, equinox, ecliptic, and epoch, but are made. To summarize, to calculate the distance, we should do the following: Calculate **Earth radius** at each point. Calculate geocentric latitude at each point. Convert spherical coordinates of each point to cartesian coordinates, from calculated **radius**, geocentric latitude, and longitude to x,y,z. Calculate distance using Euclidean distance formula.

The **Equator** is a circle of latitude, about 40,075 km (24,901 mi) in circumference, that divides **Earth** into the Northern and Southern hemispheres. It is an imaginary line located at 0 degrees latitude, halfway between the North and South **poles**.. In spatial (3D) geometry, as applied in astronomy, the **equator** of a rotating spheroid (such as a planet) is the parallel (circle of. **Earth** **radius**. Since the **Earth** is flattened at the **poles** **and** bulges at the **equator**, geodesy represents **Earth's** shape with an oblate spheroid. The oblate spheroid, or oblate ellipsoid, is an ellipsoid of revolution obtained by rotating an ellipse about its shorter axis. It is the regular geometric shape that most nearly approximates the shape of.

The fact that the

Earthis rotating about its polar axis affects the escape velocity from the surface of the planet. Taking into account theEarth'srotation, the escape velocity at the NorthPoleis: greater than the escape velocity at the. 1) The magnitude of acceleration due to gravity at the surface ofearthis given as, g = GM/R 2. Where, M = mass ofearth, R=radiusofearth, G = universal gravitational constantand. 2) We know that theearthis flattened atpoles, so theradiusofearthatthepolesis small, then the value of acceleration due to gravity can be given as, g. Google This is a digital copy of a book that was preserved for generations on library shelves before it was carefully scanned by Google as part of a project to make the world's books discoverable online.

The **Earth's** revolution around the Sun moves the stars in little circles thanks to the aberration of light, and their light can be bent and their images shifted by the gravity of the Sun, Jupiter, and Together they give Skyfield an accurate assessment of the direction of the **poles** **and** **equator** on a given date.

The equatorial **radius of earth** formula is defined as is the distance from the center **of Earth** to a point on its surface. Its value ranges from a near-maximum 6,378 km at the **equator** to a near minimum 6,357 km at either **pole** is calculated using **Radius of Earth** = Geostationary **radius**-Geostationary height..It is obvious that the points on the **Equator** revolve on a circle with the.

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The equatorial **radius** **of** **earth** formula is defined as is the distance from the center of **Earth** to a point on its surface. Its value ranges from a near-maximum 6,378 km at the **equator** to a near minimum 6,357 km at either **pole** is calculated using **Radius** **of** **Earth** = Geostationary **radius**-Geostationary height..It is obvious that the points on the **Equator** revolve on a circle with the largest **radius**. This is the distance around the **equator** of the **Earth**. If you measure the circumference of the **Earth**, while passing through the **poles**, the. Equatorial Circumference. Metric: ... it is simply double the **radius**: D = 2 * R = 2 * 14 = 28 cm. Use our circumference.

**Earth's** circumference is the distance around **Earth**. Measured around the Equatorpolesof **Earth's** circumference has been important to navigation since ancient times. The first known scientific measurement and calculation .... "/> fire in paradise netflix; train accident today fresno ca; macbook pro 2020 charging indicator. (b) Start with something you know: there are 90◦ of latitude between the North **Pole** **and** the **equator**. This distance is also one-quarter of **Earth's** So there is no single distance that can represent 1◦ of longitude everywhere on **Earth**. 51. From Appendix E, the Moon's orbit has a **radius** **of** 384, 400. (a) Difference between the value of g **at pole and equator of Earth** of **radius** 6.37 × 10 6 m is (i) equal (b) Torque due to gravity on a body about its C.M. (ii) 3.37 × 10-2 ms-2 (c) **Earth**’s attraction for 2kg of iron and attraction of 2kg of iron on **Earth** (iii) zero.

**Earth** is not a perfect sphere (slightly bulging out at the **equator**) its **radius** decreases as we move from the **equator** to the **poles**. At the **equator** and at sea level its value is about 9.78 m/s2 and. The size and shape it refers to depend on context, including the precision needed for the model. The sphere is an approximation of the figure of the **Earth** that is. As we know that g α 1R2α 1R2 , where R is the **radius** of the **earth**. And we know that **Earth** is not a perfect square. It is flattened at the **poles** and bulges at the **equator**.

But the increase of **radius** **of** the **earth** **at** **equator** from that at **poles** by about 21 km make the ellipsoid shape is better approximation for **earth** than spheroid shape, (Figure 4). The centrifugal force reach maximum value at **equator** **and** its minimum value, which equal zero at **poles**. The bulge of the **Earth's** **equator** Assuming the **Earth** is exactly spherical, we expect gravity to always point towards the center of **Earth**. ... Jupiter rotates in just under 10 hours and has an equatorial **radius** about 11 times that of **Earth**, creating a much stronger centrifugal force. As a result, in spite of a surface gravity 2.64 times stronger. **Earth** revolves on its axis once every 24 hr. Assuming that **Earth's radius** is $6400 \mathrm{km},$ find the following. (**a) angular speed of Earth in radians** per day and radians per hour (b) linear speed at the North **Pole** or South **Pole** (c) linear speed at Quito, Ecuador, a city on the **equator**.

**Earth** is not a perfect sphere (slightly bulging out at the **equator**) its **radius** decreases as we move from the **equator** to the **poles**. At the **equator** and at sea level its value is about 9.78 m/s2 and.

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The **radius** **of** **Earth** **at** the **equator** is 3,963 miles (6,378 kilometers), according to NASA's Goddard Space Flight Center. However, **Earth** is not quite a sphere. The planet's rotation causes it to bulge at the **equator**. **Earth's** polar **radius** is 3,950 miles (6,356 km) — a difference of 13 miles (22 km). Transcribed image text: Exercise 2: **Earth's** rotation The **Earth** is a sphere (almost) that rotates once per day (every 24 hours) around its own axis (an imaginary line drawn through the center of the planet between the north **pole** and the south **pole**). Eqguator ongitue apricos https /funcyeardceography weebly.com atitude-and-iongitude.am A. Locate the **equator** of the **Earth**.

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. The equatorial **radius of earth** formula is defined as is the distance from the center **of Earth** to a point on its surface. Its value ranges from a near-maximum 6,378 km at the **equator** to a near minimum 6,357 km at either **pole** is calculated using **Radius of Earth** = Geostationary **radius**-Geostationary height..It is obvious that the points on the **Equator** revolve on a circle with the. ll The **Earth** has a **radius** **of** 6.37X106. m, but from a gravitational point **of**. view, it acts like all of the mass is. ll So a round sphere is still a very good representation of the shape of the **Earth**. How different is the force of gravity at the North **Pole** **and** **at** the **Equator**?.

Therefore, assuming the entire mass of the **earth** is located at its center, we can calculate the force **of earth's** gravity at the **equator** and at the **poles**. ... at the North **Pole**, you will weigh 198 pounds (89.8 kg) at the **equator**. Note that we have focused on the **equator** and the **poles** as the extremes, but the same effect applies to all latitudes. The rotational velocity of the **Earth**, , is very small (4.2 x 10-3 degrees per second), but the **radius** of the **Earth** is very large (about 6.37 x 10 6 meters at the **Equator**). The rotational velocity looks even smaller when expressed in radians (of course it isn't really smaller!), which is a necessary conversion to use it in :. The **radius of Earth** at the **equator** is 3,963 miles (6,378 kilometers), according to NASA's Goddard Space Flight Center. However, **Earth** is not quite a sphere. The planet's rotation causes it to bulge at the **equator**. **Earth's** polar **radius** is 3,950 miles (6,356 km) — a difference of 13 miles (22 km). Or you can say 15 degree of drift in an hour. -The **Earth's** total surface area is about 197 million square miles (510 million square km).-Around 71% is protected by water and 29% by land.-The World isn't exactly a sphere. At the **equator**, the rotation of the **earth** causes it to bulge.

Assume there's a person standing at the **pole** **of** the **earth**. When the **earth** rotates, he/she has no tangential velocity because the person is at the **pole**. ... but it's enough to add up to 1670 kph over the 20,000,000 or so steps between **pole** **and** **equator**. You might want to google for "Coriolis force". Last edited: Oct 6, 2012. Oct 6, 2012 #4. The equatorial **radius of earth** formula is defined as is the distance from the center **of Earth** to a point on its surface. Its value ranges from a near-maximum 6,378 km at the **equator** to a near minimum 6,357 km at either **pole** is calculated using **Radius of Earth** = Geostationary **radius**-Geostationary height.**Earth** has an imaginary axis or a line, that starts at the top of the **earth** at. The **Equator** is the imaginary on the **Earth's** surface that is equidistant from the two **poles** **of** the **Earth**, thus dividing the planet into the Northern and the Southern Hemispheres. The countries on the **equator** generally have a tropical rainforest or equatorial climate. Distinct seasons are usually absent.

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**Earth's** equatorial diameter is 7,926 miles (12,756 km), but from **pole** to **pole**, the diameter is 7,898 miles (12,714 km) — a difference of only 28 miles (42 km). • The circumference **of Earth** at the **equator** is about 24,874 miles (40,030 km), but from **pole**-to-**pole** — the meridional circumference — **Earth** is only 24,860 miles (40,008 km) around. So, now you would have understood that **radius of earth** is not constant, distance of any point on the **poles** from the center is less than the distance of any point on the **pole** to the **equator**. Thus, force felt by the object at the **pole** is greater than the force felt by the same object at the **equator**. As a consequence, weight (i.e nothing but force.

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The **radius of Earth** at the **equator** is 3,963 miles (6,378 kilometers), according to NASA's Goddard Space Flight Center. However, **Earth** is not quite a sphere. The planet's rotation causes it to bulge at the **equator**. **Earth's** polar **radius** is 3,950 miles (6,356 km) — a difference of 13 miles (22 km).

The **radius** **at** the **Equator** is 3,963 miles The **radius** through at **Poles** is 3,950 miles What is the size of the **earth** according to **radius**? The **radius** **of** the **earth** is about 3,970 miles at the **equator**, a. -The **Earth's** total surface area is about 197 million square miles (510 million square km).-Around 71% is protected by water and 29% by land.-The World isn't exactly a sphere. At the **equator**, the rotation of the **earth** causes it to bulge. The polar **radius** **of** **Earth** is 3,950 miles (6,356 km), a 13-mile difference (22 km). This is the distance around the **equator** of the **Earth**. If you measure the circumference of the **Earth**, while passing through the **poles**, the. Equatorial Circumference. Metric: ... it is simply double the **radius**: D = 2 * R = 2 * 14 = 28 cm. Use our circumference.

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But the increase of **radius** **of** the **earth** **at** **equator** from that at **poles** by about 21 km make the ellipsoid shape is better approximation for **earth** than spheroid shape, (Figure 4). The centrifugal force reach maximum value at **equator** **and** its minimum value, which equal zero at **poles**. Orbital inclination is the angle between the plane of an orbit and the **equator**. An orbital inclination of 0° is directly above the **equator**, 90° crosses right above the **pole**, and 180° orbits above the **equator** in the opposite direction **of Earth**’s spin. (NASA illustration by Robert Simmon.). The polarity of **Earth's** magnetic **poles** has also changed over time and has undergone **pole** reversals. This was significant as we learnt more about plate tectonics in The geographic **poles** are at latitudes of 90°N (North **Pole**) **and** 90°S (South **Pole**), whereas the **Equator** is at 0°. An alignment at Greenwich.

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In 1980 the **Earth's** equatorial **radius** was fixed to a reference value nearest to the meter (6 378 137 m) by the International Union of Geodesy and Geophysics.[1] This gives the Comparison of the data showed clearly that the **Earth** is an oblate ellipsoid, flattened at the **poles** **and** bulging at the **equator**. This means a **radius** **of** 6,377 km (N. **pole** to **equator**-FE) or (center of sphere to **equator**-RE) That would work for either one, however, the measured surface distance from the N. **pole** to the **equator** is 10,001 km. That would give us a circumference at the **equator** **of** 62,838 km.. "/>.

If the **earth** had a **radius** **of** 10cm at the **poles** it would have a **radius** **of** 10,03cm at the **equator**. That's a 0.3mm increase, you would not notice that difference unless you measured it with precision tools. Let's look at another analogy. If you have one dude that's 175cm tall and another that's 0.3% taller he would only be 175.5cm tall. They also result from the fact that the **earth** is not truly spherical; the **earth's** surface is further from its center at the **equator** than it is at the **poles**. If the value 6.38x106 m (a typical **earth** **radius** value) is used for the distance from **Earth's** center, then g will be calculated to be 9.8 m/s2. The bulge of the **Earth's equator** Assuming the **Earth** is exactly spherical, we expect gravity to always point towards the center **of Earth**. ... Jupiter rotates in just under 10 hours and has an equatorial **radius** about 11 times that **of Earth**, creating a much stronger centrifugal force. As a result, in spite of a surface gravity 2.64 times stronger.

So, this aligns well with the **radius of Earth** at the **equator** as 6,378 km. Finally, the squashing at the **poles** is slightly less at about 6,357 km. Why Mount Chimborazo is higher than Mount Everest. Effect **of Earth** Rotation on Gyro **at Pole**. The equatorial **radius of earth** formula is defined as is the distance from the center **of Earth** to a point on its surface. Its value ranges from a near-maximum 6,378 km at the **equator** to a near minimum 6,357 km at either **pole** is calculated using **Radius of Earth** = Geostationary **radius** -Geostationary height.

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Earth radius at sea level is** 6378.137 km (3963.191 mi) at the equator.** It is** 6356.752 km (3949.903 mi)** at the poles and 6371.001 km (3958.756 mi) on average. The height above sea level of the location is added. Please enter the latitude in.

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The same object elongates the spring of the scale by a force of 9.771 N on the **Equator** **and** the **Pole**-calibrated scale thus indicates a mass of 9.772/9.805 = 0.997 kg. The **radius** **of** the **earth** **at** the **poles** is 6357 km and the **radius** **at** the **equator** is 378 km. Calculate the percentage change in.

During motion of a man from **equator** to **pole** **of** **earth**, its weight will (neglect the effect of change in the **radius** **of** **earth**) A Increase by 0.34%. B Decease by 0.34%. C. increase by 0.52%. D. Decease by 0.52%. Medium. Open in App. Solution. ... (assume R is the **radius** **of** the **earth**). Medium. A point at **pole** is closer to the center of **Earth**. Consequently, gravitational acceleration is greater there than at the **equator**. For example, shape of **Earth** accounts for actual change in the gravitational acceleration as polar **radius** is actually smaller than equatorial **radius**. A point at **pole** is closer to the center of **Earth**. Consequently, gravitational acceleration is greater there than at the **equator**. For example, shape of **Earth** accounts for actual change in the gravitational acceleration as polar **radius** is actually smaller than equatorial **radius**.

May 11, 2022 · If the **earth** had a **radius** of 10cm at the **poles** it would have a **radius** of 10,03cm at the **equator**. That’s a 0.3mm increase, you would not notice that difference unless you measured it with precision tools. Let’s look at another analogy. If you have one dude that’s 175cm tall and another that’s 0.3% taller he would only be. If the **earth** had a **radius** **of** 10cm at the **poles** it would have a **radius** **of** 10,03cm at the **equator**. That's a 0.3mm increase, you would not notice that difference unless you measured it with precision tools. Let's look at another analogy. If you have one dude that's 175cm tall and another that's 0.3% taller he would only be 175.5cm tall. To find the velocity of the **Earth** at the **equator** we must notice that we already know the period time of its rotation which is 24 hours and the **radius** which is. (b) Start with something you know: there are 90◦ of latitude between the North **Pole** **and** the **equator**. This distance is also one-quarter of **Earth's** So there is no single distance that can represent 1◦ of longitude everywhere on **Earth**. 51. From Appendix E, the Moon's orbit has a **radius** **of** 384, 400. **Earth** is not a perfect sphere (slightly bulging out at the **equator** ) its **radius** decreases as we move from the **equator** to the **poles** . At the **equator** and at sea level its value is about 9.78 m/s2 and.

Convert **pole** to **Earth**’s equatorial **radius** 1 **pole** = 7,88503267400005E-07 **Earth**’s equatorial **radius**. ... The **radius of Earth** at the **equator** is 3,963 miles (6,378 kilometers), according to NASA's Goddard Space Flight Center in Greenbelt, Maryland. However, **Earth**. **Earth** **radius**. Since the **Earth** is flattened at the **poles** **and** bulges at the **equator**, geodesy represents **Earth's** shape with an oblate spheroid. The oblate spheroid, or oblate ellipsoid, is an ellipsoid of revolution obtained by rotating an ellipse about its shorter axis. It is the regular geometric shape that most nearly approximates the shape of.

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The **earth** has two **poles**, the North **Pole** at the top and the South **Pole** at the bottom. The **earth** bulges at the centre where the **equator** of the **earth** lies, the **equator** is not the centre point but a line that passes through the centre of the **earth**. The researchers made the observation that at the **equator** the **earth**’s **radius** is around 12,756 km and.

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**Earth** is not perfectly spherical. And r is more in **equator**, g will be lower. Therefore, gravity is maximum at **poles** **and** minimum at the **equator**.

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**72 inch double** sink vanity dimensions. thickness sander harbor freight. how to fix engine timing honeywell rth8580wf troubleshooting; hytera pd485. Minimum circumference of the **Earth** = circumference of the **Earth** through the **poles** = 4 × (distance from a **pole** to the **equator**) = **Radius** of sphere of equal circumference = 40 007 863 m/2p = 40 007.863 km 6 367 449.1458 m: Difference between maximum and minimum circumference = 67.154 km: **Radius** of curvature at the **poles** = a/(1–e 2) ½ =. **72 inch double** sink vanity dimensions. thickness sander harbor freight. how to fix engine timing honeywell rth8580wf troubleshooting; hytera pd485. Earth radius (denoted as R🜨 or ) is the distance from the center of Earth to a point on or near its surface. Approximating the figure of Earth by an Earth spheroid, the radius ranges from a maximum of nearly 6,378 km (3,963 mi) (equatorial radius, denoted a) to a minimum of nearly 6,357 km (3,950 mi) (polar.

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Convert **pole** to **Earth**’s equatorial **radius** 1 **pole** = 7,88503267400005E-07 **Earth**’s equatorial **radius**. ... The **radius of Earth** at the **equator** is 3,963 miles (6,378 kilometers), according to NASA's Goddard Space Flight Center in Greenbelt, Maryland. However, **Earth**.

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Which is much more plausible, if the **earth** at the **equator** has a **radius** of 6000 km, 3300 for 45° north is OK, but this does not account for the **earths** .... mass (10 24 kg) 5.9722 volume (10 10 km 3) 108.321 equatorial **radius** (km) 6378.137 polar **radius** (km) 6356.752 volumetric mean **radius** (km) 6371.000 core **radius** (km) 3485 ellipticity. A. The **earth** angular speed is . B. When viewed from the North **Pole**, the angular velocity is positive.. C. The speed of a point on the **equator** is 463 m/s. D. The speed of a point on the **earth**’s surface halfway between the **equator** and the **pole** is 231.5 m/s.. Given that, **radius of earth** is, and Time period.

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meters from the North **Pole** to the **equator**, which is exactly 10,000 km. 2.2 Answer No.2 10,002 kilometres. The original definition of a **equator** to the North **Pole**, but measurements have improved. 2.3 Answer No.3 Easy, there are 90 degrees. This page presents a variety of calculations for latitude/longitude points, with the formulas and code fragments for implementing them. All these formulas are for calculations on the basis of a spherical **earth** (ignoring ellipsoidal effects) - which is accurate enough* for most purposes [In fact, the **earth**. The north celestial **pole** is directly above the **earth**’s North **Pole**. The dome of the sky is thousands of miles in **radius**, comparable in size to the **radius** of the flat **earth**.1 The **earth** does not rotate, but rather the dome of the sky spins around the north celestial **pole** each day. Because the dome of the sky is only thousands of miles across, an. An arc of 1 radian = the radial distance of the the latitude circle, from. the center.of the **Earth**. 1o = π 180 radian. At the **equator**, θ = 0 and this arc length = 111.32 km, nearly. At Baltimore, θ = 39.48o and the length is 111.16 km, nearly. At the **poles**, θ = 90o and the length = 110.95 km, nearly. Note that this arc is along a great circle. Gravitation. Why does a body weigh more **at poles** than at **equator**? A rocket is fired from the **earth** towards the sun. At what distance from the **earth**’s. centre is the gravitational force on the rocket zero ? Mass of the sun = 2× 10 30 kg, mass of the **earth** = 6× 10 24 kg. Neglect the effect of other planets etc. (orbital **radius**.

Which is much more plausible, if the **earth** at the **equator** has a **radius** of 6000 km, 3300 for 45° north is OK, but this does not account for the **earths** .... mass (10 24 kg) 5.9722 volume (10 10 km 3) 108.321 equatorial **radius** (km) 6378.137 polar **radius** (km) 6356.752 volumetric mean **radius** (km) 6371.000 core **radius** (km) 3485 ellipticity.

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This is the distance around the **equator** of the **Earth**. If you measure the circumference of the **Earth**, while passing through the **poles**, the. Equatorial Circumference. Metric: ... it is simply double the **radius**: D = 2 * R = 2 * 14 = 28 cm. Use our circumference. Geocentric gravitational constant Equatorial **radius** **of** the **Earth** Dynamical form factor Nominal mean **Earth's** **of** the **pole** **at** J2000.0 relative to the ICRS celestial **pole** has been estimated by using (a) the The ICRF positions are independent of the **equator**, equinox, ecliptic, and epoch, but are made.

The north celestial **pole** is directly above the **earth**’s North **Pole**. The dome of the sky is thousands of miles in **radius**, comparable in size to the **radius** of the flat **earth**.1 The **earth** does not rotate, but rather the dome of the sky spins around the north celestial **pole** each day. Because the dome of the sky is only thousands of miles across, an.

Minimum circumference of the **Earth** = circumference of the **Earth** through the **poles** = 4 × (distance from a **pole** to the **equator**) = **Radius** of sphere of equal circumference = 40 007 863 m/2p = 40 007.863 km 6 367 449.1458 m: Difference between maximum and minimum circumference = 67.154 km: **Radius** of curvature at the **poles** = a/(1–e 2) ½ =.

The first use calls for the physical **radius** of the **earth**. The second use call for the "**radius** of curvature" of the **earth**. For a sphere, these are identical. In reality the **earth** is "flattened" at the **poles** due to the rotation of the **earth**. The polar **radius** is 23 km (14 miles) shorter than the equatorial **radius**. A better.

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Looking at the figure above, point P is on the circle at a fixed distance r (the **radius** ) from the center Use bottom slider to adjust sphere diameter 2) Using some mathematics: First, generate a point on the surface of a sphere, THEN choose a **radius** 5 and 0 ≤ V ≤ 0 Google Meet Stuck On Loading 0 ≤ φ ≤ π is the longitude (the lines.